Question

verify the zero of the folowing p(x)=9x^2-1
x=-1/3​

Answer 1

Answer:

$p(x) = 9 {x}^{2} - 1 \\ \\ \\ = > x = - \frac{1}{3} \\ \\ \\ = > p( \frac{ - 1}{3} ) = 9 {( \frac{ - 1}{3} })^{2} - 1 \\ \\ = > 9 \times \frac{1}{9} - 1 \\ \\ = > 1 - 1 = 0$

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Answer 2

Step-by-step explanation:

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