Verify weather the following zeros of the polynomials,indicated against them:
p(y)=y^4 -3y^2+23+1 ,y=1
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Step-by-step explanation:
p(y) = y⁴- 3y² + 23 + 1
=⟩ p(1) = (1)⁴ - 3×(1)² + 23 + 1
=⟩ p(1) = 1 - 3×1 +24
=⟩ p(1) = 1 - 3 + 24
=⟩ p(1) = 25 - 3
=⟩ p(1) = 22
SINCE, THE REMAINDER IS NOT ZERO
THEREFORE, 1 IS NOT THE ZEROES OF THE GIVEN POLYNIMIALS
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