Math, asked by prati2036, 10 months ago

Verify weather the following zeros of the polynomials,indicated against them:

p(y)=y^4 -3y^2+23+1 ,y=1

Answers

Answered by anantpratik2003
2

Step-by-step explanation:

p(y) = y⁴- 3y² + 23 + 1

= p(1) = (1) - 3×(1)² + 23 + 1

= p(1) = 1 - 3×1 +24

= p(1) = 1 - 3 + 24

= p(1) = 25 - 3

= p(1) = 22

SINCE, THE REMAINDER IS NOT ZERO

THEREFORE, 1 IS NOT THE ZEROES OF THE GIVEN POLYNIMIALS

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