verify: x3+y3=(x+y)(x2-xy+y2)
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Answered by
14
two methods for you one show pic and one here :---
R.H.S => (x+y) ( x2 - xy + y2)
=> x3 - x2y + xy2 + x2y - xy2 + y3
{On multiplying x3 + y3 with (x+y) ( x2 - xy + y2)}
=> [x3 + y3] + ( -x2y + x2y) + ( xy2 - xy2)
=> x3 + y3
Since R.H.S = L.H.S,
That is x3 + y3 = x3 + y3
Hence, verified that
x3 + y3 = (x+y) ( x2 - xy + y2)
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princejGoyal:
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Answered by
4
hey mate
verify here
x^3 +y^3= (x+y)(x^2-xy+y^2)
take R.H.S.
SO,
=(x+y)(x^2-xy+y^2)
=x^3-(x)^2y+ x(y)^2+(x^2)y- x(y)^2+y^3
= x^3+ y^3
= L.H.S.
I HOPES ITS HELP'S U.
@ABHI.
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