Question

Vertical velocity of ball thrown upward -----with time? Decrease with time doubles with time Decreases parabolically

Answer 1

Answer:

Mathematically:

You have the equation of finding gravity based on the distance the ball is from ground or whatever point and the time it takes for the ball to land back onto the ground from when it was launched.

2D/T^2=g

Now, we know that D/T = V or the average velocity.

So we substitute this equation in, we get:

2V/T=g

Logically: I believe that there are 2 vertical velocities in the path of the projectile. V1 is the velocity as the ball goes up and V2 is the velocity as the ball goes down.

In this sense:

V1=V2 based on the fact that gravity is accelerating or decelerating both velocities at the same rate.

V1(Initial Velocity)= V2(Final Velocity)

V1(final Velocity)=V2(initial velocity)

In conclusion, V1 only describes the motion of the ball as it goes up and then V2 describes the motion of the ball as it comes down.

So having both velocities would define the entire motion of the ball.