(vi) 6x^3 +7x^2 - x - 2 by 3x +2
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1
Answer:
The spring constant can be found out by
k=
x
F
=
0.01
4×10
=4000N/m
Now, when two springs are connected in series, their equivalent constant is
k
eq
1
=
4000
1
+
4000
1
k
eq
=2000N/m
Therefore, mass of 6 kg will descend by
x=
2000
6×10
=0.03m=3cm
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