Physics, asked by tejespatil54, 2 months ago

vi) Critical angle between glass and air becomes (

ag = 3/2):

a) 41 48 b) 45 40 c) 35 20 d) 30 40​

Answers

Answered by sakshideshmukh72193
0

Answer:

Answer

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Correct option is

A

62

28

Critical angle sinθ

c

=

n

1

We get n=

sinθ

c

1

We will use the relation 1

o

=60

For glass :

Critical angle θ

c

=41

o

48

=41

o

+

60

48

=41

o

+0.8

o

=41.8

o

Refractive index for glass n

g

=

sin(41.8)

1

=

0.66

1

=1.5

For water :

Critical angle θ

c

=48

o

36

=48

o

+

60

36

=48

o

+0.6

o

=48.6

o

Refractive index for water n

w

=

sin(48.6)

1

=

0.75

1

=1.33

For water-glass interface :

Critical angle sinθ

c

=

n

g

n

w

=

1.5

1.33

=0.887

⟹ θ

c

=sin

−1

(0.887)=62.46

o

We get θ

c

=62

o

+ (0.46×60)

=62

o

28

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