Vitellium (Vi) has the following composition: Vi–188: 187.9122 amu; 10.861% Vi–191: 190.9047 amu; 12.428% Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?
A. It will be equal to the arithmetic mean of the masses of the three isotopes.
B. It will be closer to the mass of Vi–188.
C. It will be closer to the mass of Vi–193.
D. It will be equal to the mass of Vi–193
Answers
Explanation:
The average atomic mass is the WEIGHTED AVERAGE of the individual isotopic masses....
And so....we take the sum.....
{
187.9122
×
10.861
%
+
190.9047
×
12.428
%
+
192.8938
×
76.711
%
}
⋅
amu
=
192.1055
⋅
amu
...this is CLOSE to the mass of the MOST abundant isotope....
Answer:
The correct answer is C. It will be closer to the mass of Vi–193.
Explanation:
Based on the information provided, the common atomic mass of vitellium can be calculated via taking the weighted common of the hundreds of the three isotopes. Since Vi–193 has the perfect relative abundance, the common atomic mass of vitellium will be closest to the mass of Vi–193.
The common atomic mass of vitellium can be decided via taking the weighted common of the hundreds of the three isotopes. Vi–188 has a mass of 187.9122 amu and debts for 10.861% of vitellium, whilst Vi–191 has a mass of 190.9047 amu and bills for 12.428%. Lastly, Vi–193 has a mass of 192.8938 amu and bills for 76.711%. Due to the excessive relative abundance of Vi–193, the common atomic mass of vitellium will be closest to the mass of Vi–193. Thus, the reply is C. It will be nearer to the mass of Vi–193.
The correct answer is C. It will be closer to the mass of Vi–193.
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