Question

Volume strength of 0.715M pf H2O2 solution

Answer 1

Answer:

The molarity of H2O2 solutions will be 1.5 M

- The reaction of hydrogen peroxide can be written as :

2H2O2 ----> 2H2O +O2

- let the molarity of H2O2 be M.

- Now, we have a solution of M moles of H2O2 in 1L solution .

- From the reaction stoichiometry, 2 moles of H2O2 gives out 1 mole of oxygen = 22.4L at S.T.P

⇒1 mole of H2O2 = 11.2 L of O2

so, M mole of H2O2 = 11.2 x M L of O2

- 1 L of H2O2 gives 11.2 x M L of O2

i.e., Vol strength of H2O2 = 11.2 x M

- Putting the value, we get

16.8 = 11.2 x M

⇒M = 16.8/11.2

 M = 1.5 M

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Answer 2

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${\huge{\purple{ answer :}}}$

The molarity of H2O2 solutions will be 1.5 M

- The reaction of hydrogen peroxide can be written as :

2H2O2 ----> 2H2O +O2

- let the molarity of H2O2 be M.

- Now, we have a solution of M moles of H2O2 in 1L solution .

- From the reaction stoichiometry, 2 moles of H2O2 gives out 1 mole of oxygen = 22.4L at S.T.P

⇒1 mole of H2O2 = 11.2 L of O2

so, M mole of H2O2 = 11.2 x M L of O2

- 1 L of H2O2 gives 11.2 x M L of O2

i.e., Vol strength of H2O2 = 11.2 x M

- Putting the value, we get

16.8 = 11.2 x M

⇒M = 16.8/11.2

 M = 1.5 M

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