Volume V1 mL of 0.1M K2Cr2O7 is needed for complete oxidation of 0.678 g N2H4 in acidic medium. The volume of 0.3M KMnO4 needed for same oxidation in acidic medium will be:? 1) 2/5 V1 2) 5/2 V1 3) 113V1 4) none
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1
Answer:
Explanation:
equivalent remains same
molarity*volume=k
volume has inverse relation with molarity
volume1 / volume2 = molarity2/molarity1
volume2=volume1*molarity1/molarity2
volume2 = v1/3
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1
Answer:
201 v1/5 is the answer ....but it is not in the options.....I think that option a is correct
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