WAP in JAVA to check whether a number is pronic or not !
A pronic number is n * ( n + 1 ) = number
Fast please
Answers
Answered by
3
CODE :
import java.util.*;
class pronic_number
{
public static void main(String args[ ])
{
Scanner sc=new Scanner(System.in);
System.out.println("Enter a number to check whether it is pronic number or not");
int n=sc.nextInt();
int flag=0;
for(int i=1;i<=n;i++)
{
if(i*(i+1)==n)
{
flag=1;
break;
}
}
if(flag==0)
{
System.out.println(n+" is not a pronic number");
}
if(flag==1)
{
System.out.println(n+" is a pronic number");
}
}
}
OUTPUT :
pronic_n1.main();
Enter a number to check whether it is pronic number or not
72
72 is a pronic number
Hope it helps :-)
___________________________________________________________________
Anonymous:
Great !!!
Answered by
2
Java Code:
import java.util.Scanner;
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Input a number : ");
int num = sc.nextInt();
int ans = 0;
for(int i=0; i<num; i++)
{
if(i*(i+1) == num)
{
ans = 1;
break;
}
}
if(ans == 1)
System.out.println("Pronic Number.");
else
System.out.println("Not a Pronic .");
}
}
import java.util.Scanner;
public static void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.print("Input a number : ");
int num = sc.nextInt();
int ans = 0;
for(int i=0; i<num; i++)
{
if(i*(i+1) == num)
{
ans = 1;
break;
}
}
if(ans == 1)
System.out.println("Pronic Number.");
else
System.out.println("Not a Pronic .");
}
}
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