Question

Water is flowing at the rate of 7m/s through a circular pipe of internal diameter of 4 cm into a cylindrical tank the radius of whose base is 40 cm find the increase in water level in 30 min

Answer 1

As Given,
Diameter of Pipe = 4 cm
Radius of pipe = 4/2 cm = 2 cm
Velocity of water = 7 m/s = 700 cm/s


$= > volume = \pi \: {r}^{2} \times rate \:$
=> V = 22/7 x 2 x 2 x 700
=> V = 8800 cm^3

As we know that,

=> 30 min = (30 x 60)s = 1800 s

=> Volume of water in 30 min or 1800s = 8800 x 1800

As we know that,

Volume of water in Tank = Volume of water flow in 30 min or 1800s

$= > \pi \: {r}^{2} h = 8800 \times 1800$
=> 22/7 x 40 x 40 x h = 8800 x 1800
=> 5028.58 x h = 15840000
=> h = 15840000/5028.58
=> h = 3150.19 cm
=> h = 3150.19/100 m = 31.5019 m


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