water is pouring into a conical vessel of daimeter 5.2 m and slant height 6.8m at the rate of 1.8m^3 per minute. Hpw long it takes to fill the vessel
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Answered by
7
first we find volume of conical vessel=pi.r^2.h/3
but h is not given
so , we find h=root {(6.8)^2-(2.6)^2}=6.24m (approx)
now volume=22/7 x (2.6)^2 x (6.24)/3
=44.15 m^3
now time =volume /rate
=44.15/1.8=24.52minutes (approx)
but h is not given
so , we find h=root {(6.8)^2-(2.6)^2}=6.24m (approx)
now volume=22/7 x (2.6)^2 x (6.24)/3
=44.15 m^3
now time =volume /rate
=44.15/1.8=24.52minutes (approx)
mysticd:
thank you very much
try to write formula wherever required
here , h=? and v=?
okay
abhi u did well , i w'll give u brainliest next time
Answered by
11
Diameter = 5.2 m
Radius = 2.6 m
l = 6.8 m
Rate = 1.8m^3/min
l^2 = r^2 + h^2
(6.8)^2 = (2.6)^2 + (h)^2
h^2 = 46.24 - 6.76
h = 6.28
Volume of the cone = πr^2h/3
= π×6.76×6.28/3
= 44.47 m^3
Time required to fill the vessel
= 44.47/1.8
= 24.70 min
= 24 min 42sec
Radius = 2.6 m
l = 6.8 m
Rate = 1.8m^3/min
l^2 = r^2 + h^2
(6.8)^2 = (2.6)^2 + (h)^2
h^2 = 46.24 - 6.76
h = 6.28
Volume of the cone = πr^2h/3
= π×6.76×6.28/3
= 44.47 m^3
Time required to fill the vessel
= 44.47/1.8
= 24.70 min
= 24 min 42sec
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