Physics, asked by immanuelThomasj, 10 months ago

water waves in a Shallow dish are 10 cm long the water oscillates up and down at the rate of 4.8 oscillations per second what is the time period​

Answers

Answered by mouseears2
0

Answer:

The time period is T = 0.21 s.

Explanation:

This is because f = 4.8 Hz.

Answered by chaviLOVER
1

Answer:

The relationship between the velocity of the wave, its wavelength and frequency is given by the formula

Wavelength\quad \lambda =\dfrac { Speed\quad (v) }{ Frequency\quad (\nu) } Wavelengthλ=

Frequency(ν)

Speed(v)

,

where, vv - velocity of the wave

\lambda λ - wavelength of the wave

ff - frequency of the wave.

In the question it is given that the frequency is 4.8 Hz and the wavelength is 6.0 cm, that is, 0.06 meters.

The velocity of the sound is calculated as follows.

v=f\times \lambda = 4.8 \ Hz\times 0.06 \ m = 0.288 \ m/sv=f×λ=4.8 Hz×0.06 m=0.288 m/s

Hence, the speed of the water wave is 0.288 m/s.

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