Weight (in grams) required
to break the thread of
-Silk
-nylon
-wool
-cotton
-polyester
Answers
Let the weight of the fireman be mg and his downward acceleration be a.
Breaking strength of rope T=
3
2
mg (given)
∴ ma=mg−T
OR ma=mg−
3
2
mg
OR ma=
3
1
mg ⟹a=
3
g
solution
PHYSICS
avatar
Asked on October 15, 2019 by
Sreetama Mall
With what minimum acceleration can a fireman slide down a rope while breaking strength of the rope is
3
2
of the weight?
Share
Study later
VIDEO EXPLANATION
ANSWER
Let the weight of the fireman be mg and his downward acceleration be a.
Breaking strength of rope T=
3
2
mg (given)
∴ ma=mg−T
OR ma=mg−
3
2
mg
OR ma=
3
1
mg ⟹a=
3
g
solution
PHYSICS
avatar
Asked on October 15, 2019 by
Sreetama Mall
With what minimum acceleration can a fireman slide down a rope while breaking strength of the rope is
3
2
of the weight?
Share
Study later
VIDEO EXPLANATION
ANSWER
Let the weight of the fireman be mg and his downward acceleration be a.
Breaking strength of rope T=
3
2
mg (given)
∴ ma=mg−T
OR ma=mg−
3
2
mg
OR ma=
3
1
mg ⟹a=
3
g
solution