Question

Weight of an object on earth is 196 N. What will be its weight on the surface of the moon, if acceleration due to gravity on the surface of the moon is one sixth of that on earth ? What will be it's mass on the surface of the earth and on the surface of the moon ? (Given that g=9.8ms -2 )

Answer 1

Answer:

32.7

Explanation:

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Answer 2

Answer:

The weight of the object on the moon's surface is 32.66 N.

The object's mass on earth is 20 Kg.

The object's mass on the surface of the moon is 20.03 Kg.

Explanation:

Given,

Weight of the object on earth, $W_{E}$ = 196 N

Acceleration due to gravity on earth, $g_{E}$ = 9.8 m/s²

Acceleration due to gravity on the moon's surface, $g_{M}$ = $\frac{1}{6} th$ of $g_{E}$

Weight of the object on the moon's surface, $W_{M}$ =?

The object's mass on earth, $m_{E}$ =?

The object's mass on the surface of the moon, $m_{M}$ =?

As we know,

• The acceleration due to gravity on the surface of the moon is one-sixth of that on earth.

Therefore,

• $W_{M} = \frac{1}{6} \times W_{E}$

Here,

• $W_{M}$ = Weight of the object on the moon's surface
• $W_{E}$ = Weight of an object on the earth

After putting the value of $W_{E}$ in the equation, we get:

• $W_{M} = \frac{1}{6} \times 196$
• $W_{M} = 32.66 N$

Therefore, the weight of the object on the moon's surface = 32.66 N

As we know,

• Weight = mass × acceleration due to gravity

Therefore,

• Weight of the object on the earth = mass of the object × $g_{E}$
• The mass of the object on earth = $\frac{W_{E}}{g_{E}}$
• The mass of the object on earth =$\frac{196}{9.8}$ = 20 Kg

Also,

• The mass of the object on the moon's surface = $\frac{W_{M}}{g_{M}}$
• The mass of the object on the moon's surface = $\frac{32.66}{9.8/6}$ = $\frac{32.66}{1.63}$ = 20.03 Kg