Question

Wgat should be subtracted from p(x)=x2-16x+30 so that 15 is the zero of tge resulting polynomial

Answer 1

p(x)=x2 -16x+30,

p(15)=152 -16*15+30

p(15)=225-240+30

p(15)=15

therefore 15 should be subtracted from p(x) so that 15 is the zero of the resulting polynomial

Answer 2

Answer:

The required number is 15.

Step-by-step explanation:

To find : What should be subtracted from $p(x)=x^2-16x+30$ so that 15 is the zero of the resulting polynomial ?

Solution :

The given polynomial is $p(x)=x^2-16x+30$

As 15 is the zero we put x=15,

$p(15)=(15)^2-16(15)+30$

$p(15)=225-240+30$

$p(15)=15$

Which means 15 should be subtracted from p(x) so that 15 is the zero of the resulting polynomial.

Therefore, The required number is 15.