Chemistry, asked by gnsurabhi, 1 year ago

what are factors on which liquefaction of gases depends on?
please answer only if u know and state the reasons

Answers

Answered by slnvirat
2
THIS IS A VERY DETAILED EXPLANATION OF THE REQUIRED CONTENT:


The liquefaction of a gas takes place when the intermolecular forces of attraction become so high that they bind the gas molecules together to form the liquid state.

The intermolecular forces of attraction can be increased either by increasing the pressure so that the molecules come close together or by cooling the gas so that the kinetic energy of the molecules decreases and they become slower.

The effect of temperature on the liquefaction of gases is found to be very important as higher the temperature of the gas ,more difficult it is to liquefy it and higher is the pressure required.

Gas like hydrogen ,helium, oxygen, nitrogen could not be liquefied at room temperature by application of pressure alone. Each of these gases could also be liquefied provided first it is cooled down to or below a particular temperature. For each gas, there is a particular temperature above which it cannot be liquefied, howsoever, high pressure may be applied on the gas. This temperature is called critical temperature.

Critical temperature of a gas may be defined as that temperature above which it cannot be liquefied however high pressure may be applied on the gas.

The pressure required to liquefy the gas at the critical temperature is called critical pressure .

The volume occupied by 1 mole of the gas at critical temperature and critical pressure is called critical volume.

All the three are called critical constants of the gas and are represented by Tc, Tp, Tv.

Andrews experiment on critical phenomena

Andrews in 1861 was the first to study the critical phenomena experimentally using carbon dioxide gas.

He studied the effect of pressure on the volume of carbon dioxide at different constant temperature. The plots obtained are called isotherms.

At the lowest temperature employed i.e. 13.1° C , at low pressure, carbon dioxide exist as a gas, as shown at the point A.

As the pressure is increased, the volume of the gas decreases along the curve.

The point at which liquefaction of the gas starts, volume decreases rapidly  because liquid has much less volume than the gas.

Once the liquification is complete, the increase in pressure has very little effect upon volume because liquids are very little compressible..Hence a steep curve is obtained.

As the temperature is increased, horizontal portion becomes smaller and smaller and at 30.98 °C , it is reduced to a point E.

Above 30.98°C ,the gas cannot be liquefied at all, however high pressure may be applied. Thus 30.98°C is the critical temperature.

We get a dome shaped curve.

A point like A represent gaseous state.

A point Like D represents a liquid state.

A point within the dome shaped area represents existence of liquid and gaseous carbon dioxide in equilibrium.

gnsurabhi: thank u for the detailed answer but i needed to know the other factors other then temperature and pressure,sorry i forgot to mention it
Answered by meenuhari1402
0
  1. decrease in temperature - when the temperature decreases , at a certain point the gas condensates and becomes a liquid.
  2. increase in pressure - when the pressure increases , the freely moving particles would get closer to each other and becomes liquid.

gnsurabhi: thank u for the detailed answer but i needed to know the other factors other then temperature and pressure,sorry i forgot to mention it
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