What are the concentrations of H⁺ and OH⁻ in pure water at 25°C?
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pH=-log[H+]
since pH of pure water is 7
so 7=-log[H+]
[H+]=10^-7
pOH=-log[OH-]
So [OH-] is also=10^-7
Hope it helps..
PLEASE MARK AS BRAINLIEST IF HELPFU!!!
since pH of pure water is 7
so 7=-log[H+]
[H+]=10^-7
pOH=-log[OH-]
So [OH-] is also=10^-7
Hope it helps..
PLEASE MARK AS BRAINLIEST IF HELPFU!!!
07161020:
PLEASE MARK AS BRAINLIEST IF HELPFU!!!
Okay!
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