Question

what are the coordinaties of p?a) (4,6) b) (5,6) c)(6,0) d) (7,4)​

Answer 1

Answer:

(732,7−19)

Step-by-step explanation:

Let the coordinates of P be (x, y). Given m:n=2:5

(x1,y1)=(4,−5) and (x2,y2)=(6,3)

by section formula, 

x=m+nmx2+nx1=2+52(6)+5(4)=712+20=732

y=m+nmy2+my1=2+(5)2(3)+5(−5)=76−25=7−19

∴ Coordinates of P=(732,7−19)