Question

what are the limitation of the reaction given below
Zn(s)+ 2HCL(aq)= ZnCl2+ H2​

Answer 1

Explanation:

Zn  + 2 HCl  - - - - - - - - -> ZnCl2+ H2

For different concentrations :

0.3 moles Zn x 1 mole H2 / 1 mole Zn = 0.3 moles H2

 

0.52 moles H2 x 1 mole H2 / 2 moles HCl = 0.26 mole H2

 

Hence, HCl will be the limiting reagent in the reaction and Zn will be excess reagent. Amount of hydrogen produced will be = 0.26 moles.

Answer 2

Answer:

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Explanation:

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