Question

what are the magnitude of the gravitational force between the earth and 1 kg object on its surface

Answer 1

F=GMm/R^2 -------(1)
AS m=1 kg
G= 6.67×10^-11
M OF EARTH = 6×10^24
RADIUS OF EARTH = 6.4× 10^6
put all the values in equation (1)
and answer will be 9.77 or 9.8

Answer 2

$\huge\mathfrak{\underline{\underline{Solution:-}}}$

Mass of earth , M = 6 × ${10}^{24}$kg.

Mass of object, m = 1kg.

Distance = radius of earth (R) = 6.4 × ${10}^{6}$m.

G = 6.67 ×${10}^{-11}$ N${m}^{2}$ / ${kg}^{2}$

$f = \frac{GMm}{ {r}^{2} } = \frac{6.67 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 1 }{6.4 \times {10}^{6} }$

= 9.8 N