What do you observe when dilute sulphuric acid is treated with sodium sulphide and give balanced equatione?
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Na2S + 3H2SO4 → 2NaHSO4 + SO2 + S + 2H2O
So, it forms sodium hydrosulphide, sulfur dipxide, sulfur and water
So, it forms sodium hydrosulphide, sulfur dipxide, sulfur and water
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Answer:
Sodium sulphite reacts with sulphuric acid to produce sodium bisulfate, sulfur dioxide and water.
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