what does it mean when we are asked to show that x and y are not unique? question is -
If D is the HCF of 56 and 72 find X and Y satisfying d = 56 X + 72 Y show that x and y are not unique???
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This is based on Euclid's division algorithm:-
Euclid's division algorithm:-
a = bq + r
0 ≤ r < b
a > b
72 > 56
72 = 56 × 1 + 16
56 = 16 × 3 + 8
16 = 8 × 2 + 0
As the remainder is 0,HCF is 8
HCF of 56 and 72 is 8
d = 8
d = 56x + 72y
8 = 56 - 16×3
= 56 - [72 - 56(1)]×3
= 56 - 72×3 + 56×3
= 56×4 - 72×3
= 56×4 + 72(-3)
= 56x + 72y
Therefore, x = 4 and y = -3
Hope it helps you!
Here, we have to show that X and y are not unique, which means that we have to show/prove/solve this question is such a manner that X and y are not equal.
To show these are not unique, multiply the while equation by any natural number.
Euclid's division algorithm:-
a = bq + r
0 ≤ r < b
a > b
72 > 56
72 = 56 × 1 + 16
56 = 16 × 3 + 8
16 = 8 × 2 + 0
As the remainder is 0,HCF is 8
HCF of 56 and 72 is 8
d = 8
d = 56x + 72y
8 = 56 - 16×3
= 56 - [72 - 56(1)]×3
= 56 - 72×3 + 56×3
= 56×4 - 72×3
= 56×4 + 72(-3)
= 56x + 72y
Therefore, x = 4 and y = -3
Hope it helps you!
Here, we have to show that X and y are not unique, which means that we have to show/prove/solve this question is such a manner that X and y are not equal.
To show these are not unique, multiply the while equation by any natural number.
thoolikaasreebelli:
thank you but I did not understand the line which says show that x and y are not unique .
Here , it means that we have to show/prove x and y are not equal
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