what happens when electric current is passed through acidulated water?give reactions at two electrodes mention the product at cathode and anode.
Answers
Answered by
84
When electric current is passed through acidulated water using inert electrodes, water will be decomposed into oxygen and hydrogen.
Positive ions (H+) with move to the cathode while Negative ions (OH-) will move to the anode
At cathode: Hydrogen gas will formAt anode: Oxygen gas will form
At the cathode (negative electrode) H+ will gain electrons and form hydrogen gas;2H+(aq) + 2e– ---> H2(g)
At the anode (positive electrode)OH- will lose electrons and form oxygen gas;4OH–(aq) ---> 2H2O(l) + O2(g) + 4e–
The overall equation for the electrolysis of acidulated water is:
2H2O(l) ---> 2H2(g) + O2(g)
Positive ions (H+) with move to the cathode while Negative ions (OH-) will move to the anode
At cathode: Hydrogen gas will formAt anode: Oxygen gas will form
At the cathode (negative electrode) H+ will gain electrons and form hydrogen gas;2H+(aq) + 2e– ---> H2(g)
At the anode (positive electrode)OH- will lose electrons and form oxygen gas;4OH–(aq) ---> 2H2O(l) + O2(g) + 4e–
The overall equation for the electrolysis of acidulated water is:
2H2O(l) ---> 2H2(g) + O2(g)
Answered by
58
When electric current is passed through acidified water, it decomposes to give Hydrogen gas at cathode and oxygen gas at anode
The reaction is given below :
2H2O(l)---> 2H2 (g)+O2(g)
At cathode :
when current is passed from battery, the positive ions move towards cathode. They gain electrons and get neutralized to form H2 gas
2H+(aq) +2e---------> H2 (g)
AT Anode:
4OH-(aq) ----------> O2(g) +2H2O(l) + 4 e
The reaction is given below :
2H2O(l)---> 2H2 (g)+O2(g)
At cathode :
when current is passed from battery, the positive ions move towards cathode. They gain electrons and get neutralized to form H2 gas
2H+(aq) +2e---------> H2 (g)
AT Anode:
4OH-(aq) ----------> O2(g) +2H2O(l) + 4 e
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