Question

what ia the missing term(2x^3-3)(5a^3-2)=10a^6+_+6

Answer 1

$\tt{(2x^3 - 3)(5a^3 - 2)}$

$\tt{\implies 2x^3(5a^3 - 2) - 3(5a^3 - 2)}$

$\tt{\implies 10a^6 - 4a^3 - 15a^3 + 6}$

$\tt{\implies 10a^6 - 19a^3 + 6}$

On comparing with, $\tt{10a^6 +}$ ____ $\tt{+ 6}$, we get

$\tt{10a^6 {\red{- 19a^3}} + 6}$

Answer 2

Answer:

missing term = -19a³

Step-by-step explanation:

(2a³ - 3)(5a³ -2)

= 10a^6 -4a³ - 15a³ +6

= 10a^6 -19a³ + 16

so missing term = -19a³