Chemistry, asked by chetnasoni740, 6 months ago

What if the water levels were not equal? Calculate
the pressure inside Pipet A if the height of the water
is 15.0 mm higher than the water in Pipet B. The
atmospheric pressure is 760.6 mm Hg. Be sure to
consider the difference in units: 1 mm H2O ≠ 1 mm
Hg. Start by converting the height pressure difference
from mm H2O to mm Hg. You will find the following
formula for pressure useful for the unit conversion.

Answers

Answered by aditya0511
2

what if the water level were not equal

Answered by presentmoment
1

Answer:

      2.1 80 M

Explanation:

  • Solving party of this problem. So place all correspond to 7 60. Member of at H G. Equal to H. D. G. Which is equal to 7 60 multiplication, one m by 1000.
  • Multiplication 13.6 grandpa or ml multiplication graham meter per second. The square which will be calculated further in the next step. But first I'm just calculating the value of pressure corresponding to edge of meters.
  • So I can ride the value age please said, corresponding to razor corresponding to add meter of ach meter of equal to catch multiplication one ground by one.
  • Amoled multiplication ground meter per second squared. So from both the expression I can write a question. Edge edge multiplication, one ground by one Ml multiplication graham meter per second squared is equal to 7 60 multiplication, one m by 1000 multiplication 13.6 g per ml multi pickets and Graham meter per second square.
  • On solving it, we get the height of the column is equal to 10.3 m. Now for part B I can like places that is equal to euro 0.97 80 M. Plus At B. G two. Just putting the value in this exhibition.
  • So just look at it carefully. It will be quite lighter larger. So 0.978 p. m. plus 39ft multiplication, 30.48 centimeter per feet, multiplication, one m by 100 centimeter.
  • Multiplication, one g per centimeter cube, multiplication, one kg by 1000 g multiplication, 100 centimeter whole cube by one m cube multiplication 9.8 m per second squared on Sultan multiplication, one PA by Kg permitted second squared multiplication 1 80 m by 1013 to 5 P. A. On simplification, I get the picture of the body P at 2.1 80 M as our final answer.
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