what is a smallest number by which 59400 must be multiplied to make a perfect cube
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59400=2^3 • 3^3 • 5^2 • 11
So it should be multiplied by 5*11^2=5*121= 605
So it should be multiplied by 5*11^2=5*121= 605
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Answer- ∛59400 by Prime Factorisation Method-
Prime factors of 59400= (2×2×2)×(3×3×3)×(5×5)×(11)
As (5×5)×11 don't form triplets, we need to make them multiplied in order to form triplets. Also, these no. will multiply with the given no. to make it a perfect cube.
∴5×11×11= 605 is the smallest no. to be multiplied by 59400 to make it a perfect cube.
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If helpful, BRAINLIEST pl.
Prime factors of 59400= (2×2×2)×(3×3×3)×(5×5)×(11)
As (5×5)×11 don't form triplets, we need to make them multiplied in order to form triplets. Also, these no. will multiply with the given no. to make it a perfect cube.
∴5×11×11= 605 is the smallest no. to be multiplied by 59400 to make it a perfect cube.
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If helpful, BRAINLIEST pl.
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