what is decrease in weight of a body of mass 600 is taken in a mine of depth 500
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g(d) =g[1−dR],
where g is acceleration due to gravity, d is depth of mine and R is radius of Earth, and g(d)refers to the value of g at the depth d.
Applying the values in the above equation:
g=9.8[1−10006371000]
=9.7985m/s2.
Hence, difference in weight
=mg−mg(d)
=500(9.8–9.7985)=0.7691kg.
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