Question

what is derivative of this function w. r. t x (1) tanh (1+x^2)​

Answer 1

Answer: 2x.tanh

Step-by-step explanation:

Let y =

Since tanh is constant because it is not correlated to x

So

$\frac{dy}{dx} = tanh\frac{d}{dx}(1+ x^{2} ) \\\frac{dy}{dx} = tanh[\frac{d}{dx}(1)+ \frac{d}{dx}(x^{2} )] \\ \frac{dy}{dx} = tanh(0) + tanh(2x)\\ \frac{dy}{dx} = 2x.tanh$

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