what is greatest number of three digits which when divided by 6 9 and 12 leaves a remainder 2 in each case..
Answers
Answered by
2
Answer:
Step 1:Find L.C.M of given numbers
LCM of 6,9,12 is 36
Step 2:Find largest 3 digit number divisible by 36.
Largest 3 digit number is 999 and largest 3 digit number divisible by 36 is 972
Step 3:Add the remainder to the number.972+3=975
Answer=975
Similar questions