Question

what is greatest number of three digits which when divided by 6 9 and 12 leaves a remainder 2 in each case..​

Answer 1

Answer:

Step 1:Find L.C.M of given numbers

LCM of 6,9,12 is 36

Step 2:Find largest 3 digit number divisible by 36.

Largest 3 digit number is 999 and largest 3 digit number divisible by 36 is 972

Step 3:Add the remainder to the number.972+3=975

Answer=975