Question

what is magnetic field for semi infinite wire

Answer 1

The magnitude of the field from a semi-infinite wire is half of that of an infinite wire ( look at direct integration of the Biot-Savart law): in z direction. From the circular wire, the field is: The magnetic field from each section contributes in the same direction (z).

Answer 2

Bt $= \frac{\mu I}{4 \pi r}$ is the magnetic field for semi infinite wire.

Explanation:

We are considering a current carrying conductor that has I amount of current in it and is Semi infinite in length.

Now at a certain point 'T' that is at a distance 'r' from the semi infinite wire, the magnetic field experience will be 'e' in outward direction.

As per the the finger rule where thumb is pointing towards the direction of current.

Now to calculate the magnetic field due to semi-infinite where we can either take the integral part of the current carrying conductor or as we know the magnetic field due to infinite wire is,

                                                    B = $\frac{ \mu I}{2 \pi r}$  

                                          = 2Bt ⇒ Bt $= \frac{\mu I}{4 \pi r}$

To know more;

A semi infinite wire of uniform linear charge density is placed as shown in figure.The conical surface is of radius R and height h. the electric flux through curved surface of the cone is

Correct option is \sqrt{2} lamda/ 3 e₀

https://brainly.in/question/9978789