Question

What is magnetic flux? A current of 1.5 amperes in a 400 turns coil
produces 0.4x10-5 weber magnetized flux in each turn. Find out the
self-inductance of coil.​

Answer 1

Given:

Current (I) = 1.5 A

Number of turns (N) = 400

Magnetic flux (Ф) = 0.4 × $10^{-5}$  weber

To find:

Self-induction (L)

Solution:

• N×Ф = L×I

     ⇒400 × 0.4 × $10^{-5}$ = L × 1.5

• L = 26.27 × $10^{-5}$ H