what is ratio between h2co3 and nahco3 when the ph of body is 7.4
Answers
Answered by
4
Ka = 4.4 x 10^-7
pKa =6.4
7.4 = 6.4 + log [HCO3-]/ [H2CO3]
7.4 - 6.4 = 1
10^1 = 10 = [HCO3-]/ [H2CO3]
[H2CO3]/ [HCO3-]= 1/10 = 0.1 = 1:10
pKa =6.4
7.4 = 6.4 + log [HCO3-]/ [H2CO3]
7.4 - 6.4 = 1
10^1 = 10 = [HCO3-]/ [H2CO3]
[H2CO3]/ [HCO3-]= 1/10 = 0.1 = 1:10
Similar questions