Question

what is rationalising factor of root 27

Answer 1

Hey!

$=\sqrt{27}\\=\sqrt{3\times3\times3}\\= 3\sqrt{3}\\\\\text{Hence, Rationalizing factor of }\sqrt{27} = \sqrt{3}$

Hope It Helps You!

Answer 2

Answer:

$\sqrt{3}$ is a rationalizing factor of $\sqrt{27}$ .

Step-by-step explanation:

Explanation:

Given , $\sqrt{27}$

This can be written as ,

$\sqrt{27}$ = $\sqrt{ 3 . 3 .3 }$ = $3\sqrt{3}$ .

The "rationalizing factor" is the expression that is multiplied by an irrational expression to get a rational number.

Now , rationalize the number $3\sqrt{3}$ ,

$3\sqrt{3 }$ ×$\sqrt{3}$ = 3 × 3 = 9 .

And 9 is a rational number  and $\sqrt{3}$ is a simplest rationalize factor of $\sqrt{27 }$.

Final answer:

Hence , $\sqrt{3}$ is a  simplest rationalize factor of $\sqrt{27}$ .

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