Question

what is sin15 degree

Answer 1

sin15°
=cos (90°-15°)
=cos 75°
this is your answer

sin45°-sin30°
=cos45°-cos60°
=cos15°

Answer 2

sin(45-30)= sin45 cos30 -cos45 sin30
=
$1 \div \sqrt{2} \times \sqrt{3} \div 2 - 1 \div \sqrt{2} \times 1 \div 2$
[tex]1 \div \sqrt{2} \times \sqrt{3} \div 2 - 1 \div \sqrt{2} \times 1 \div 2 \\ \\ \sqrt{3 } \div \ \geqslant 2 \times sqrt{2} \times 1 \div 2 \times