Question

what is the amount of heat every required to convert 1g of water at 0 degree Celsius to 80 degree Celsius ​

Answer 1

Explanation:

(1 gm)(80 cal/gm) = 80 cal. (1 gm)(1 cal/gm/K)(100 K) = 100 cal. (1 gm)(540 cal/gm) = 540 cal. Summing up the entire thing you get, total heat required = 720 cal = 0.72 kcal.