What is the angle between 2N force and 3N force, so that their displacement is 4N?
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Question should be:
What is the angle between 2N force and 3N force, so that their resultant is 4N?
Answer:
Resultant Force = √(F₁² + F₂² + 2F₁F₂Cosθ)
4 = √[2² + 3² + (2 × 3 × 4 × Cosθ)]
16 - 13 = 12Cosθ
Cosθ = 1/4
θ = Cos⁻¹ (1/4)
Angle between them should be Cos⁻¹ (1/4)
What is the angle between 2N force and 3N force, so that their resultant is 4N?
Answer:
Resultant Force = √(F₁² + F₂² + 2F₁F₂Cosθ)
4 = √[2² + 3² + (2 × 3 × 4 × Cosθ)]
16 - 13 = 12Cosθ
Cosθ = 1/4
θ = Cos⁻¹ (1/4)
Angle between them should be Cos⁻¹ (1/4)
Achu999:
Thank you for your answer. But my teacher told me that the answer is cos^-1 (3/12). How will that come up? Can you please explain?
3/12 = 1/4
ooohhh thank you very muchhhh......
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