Question

what is the angle between two forces of 2N and 3N having resultant 4N​

Answer 1

Explanation:

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Let the two vectors be A and B, and their resultant be R.

• Let the angle between A and B be θ

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• A=2N

• B=3N

• R=4N

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Now R² = A² + B² + 2AB cosθ

So, 4² = 2² + 3² + 2 × 3 × 4cosθ

So, 16 = 4 + 9 + 24cosθ

So, 16 = 13 + 24cosθ

So, 3 = 24 cosθ

So, 3/24 = cosθ

So, cosθ = 1/8

So, θ = cos–¹(1/8)

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