Question

What is the angle of inclination if a weight
of 150 kg is in equilibrium and the value of m is
0.5773?

Answer 1

The weight is in equilibrium on an inclined plane. Therefore, the inclination of the plane, must be equal to the angle of repose. Given   μ=0.25  

Angle of Inclination   θ =Angle of repose   λ=tan−1(μ)=140  

Normal reaction=  Wcosθ=150×9.8×cos(140)=1426N