What is the area of a equilateral triangle whose inscribed circle has radius r?
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Hey there,
Centre of circle is circumcentre of ∆
Height of Equilateral∆ of side a,
=>3/2r=√3/2a=>a=√3r.
Area =√3/4 a^2
=√3/4(3r^2)=3√3/4 r^2.
Hope it helps
Centre of circle is circumcentre of ∆
Height of Equilateral∆ of side a,
=>3/2r=√3/2a=>a=√3r.
Area =√3/4 a^2
=√3/4(3r^2)=3√3/4 r^2.
Hope it helps
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