What is the change in gravitational potential energy when 7000 N
elevator moves from street level to the top of building 300 m
above the street level?
Answers
Answer:
2100000 joules
Explanation:
Change in potential energy = work done in raising the elevator = weight force * distance moved = mg * h
=(7000 N * 300 m)
= 2100000 joules
The change in gravitational potential energy of the elevator is 21,00,000Joules.
Given:-
Weight of elevator (mg) = 7000N
Height of the building (h) = 300m
To Find:-
The change in gravitational potential energy of the elevator.
Solution:-
We can simply find out the change in gravitational potential energy of the elevator by using the following steps.
As
Weight of elevator (mg) = 7000N
Height of the building (h) = 300m
Also, the change in gravitational potential energy of the elevator is given by
U = mg*h
U = 7000*300
U = 21,00,000joules
Hence, The change in gravitational potential energy of the elevator is 21,00,000Joules.
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