Question

What is the density of an iron block which has a volume of
12cm^3 and a mass of 96 g?

Answer 1

Answer:

Given:

Mass of block = 96 g

Volume of block = 12 cm³

To find:

Density of the block

Concept:

Density is an quantity relating mass and volume of any material. It is obtained as the ratio is mass and volume of the object.

$\boxed{ \green{ \bold{ \huge{\rho = \dfrac{mass}{volume} }}}}$

Dimensions of density :

$\boxed{ \large{ \red{ \{ \rho \} = \frac{M}{ {L}^{3}} = M {L}^{-3} }}}$

Calculation:

$\huge{ \blue{ \rho = \frac{mass}{volume} }}$

$\huge{ \blue{ = > \rho = \frac{96}{12} }}$

$\huge{ \blue{ = > \rho = 8 \: g {cm}^{ - 3} }}$

So final answer :

$\boxed{ \huge{ \orange{\rho = 8 \: g \: {cm}^{ - 3} }}}$

Answer 2

Question:-

What is the density of an iron block which has a volume of $\displaystyle\sf {12\ cm^3}$ and a mass of $\displaystyle\sf {96\ g}$?

Answer:-

$\displaystyle\Large\boxed {\sf {\rho=8\ g\ cm^{-3}}}$

Solution:-

Given,

$\displaystyle\sf {M=96\ g}$

$\displaystyle\sf {V=12\ cm^3}$

Then, density,

$\displaystyle\longrightarrow\sf{\rho=\dfrac {M}{V}}$

$\displaystyle\longrightarrow\sf{\rho=\dfrac {96\ g}{12\ cm^3}}$

$\displaystyle\longrightarrow\sf {\underline {\underline {\rho=8\ g\ cm^{-3}}}}$

In SI Units,

$\displaystyle\longrightarrow\sf {\underline {\underline {\rho=8\times10^3\ kg\ m^{-3}}}}$