Question

what is the density of neutrons is of order (a)10 to the power 3kg/cc(b)10 to the power6kg/cc(c)10 to the power 9 kg/ cc(d)10 to the power 11 kg/cc

Answer 1

Ur Answer is (d).....if u know in detail....Then Ask me

Answer 2

Answer:

yutuert

Explanation:

It is known that neutron is slightly greater in size than a proton which are present inside a nucleus.

Also, mass of proton = mass of neutron

Therefore, with the help of volume of nucleus we determine the density of neutron.

Formula to calculate density is as follows.

             Density = $\frac{/text{mass of neutron}}{/text{volume of neutron}}$

Since, it is known that mass of neutron is $1.67 \times 10^{-27}kg$

And, mass of 1 mole of a neutron = 1 g.

Hence, mass of neutron = $\frac{A}{N_{A}}$

where, $N_{A}$ = Avogadro's number = $6.023 \times 10^{23}$

As neutrons are in the shape of a circle. Hence, formula for their volume will be $\frac{4}{3} \pi r^{3}$. And, radius of a neutron is $1.33 \times 10^{-13} A^{1/3}cm$ where A = mass number.

Thus, we will calculate the density as follows.

              d = $\frac{A times 3}{6.023 \times 10^{23} \times 4 \pi (1.33 \times 10^{-13})^{3}A}$

                  = $10^{11}kg/cc$

Therefore, we can conclude that the density of neutrons is of order $10^{11}kg/cc$