Question

What is the displacement value of zinc oxide in Theobroma oil suppositories containing 40% of zinc oxide and is prepared in 1 g mould . (The weight of 8 suppositories is 11.74 g) *
70
5
12
90​

Answer 1

Answer:

Weight of drug in suppositories = 40% = 40/100 x 8.8 = 3.52. Weight of base displaced by drug = 6 - 5.28 = 0.72 g. 1g of base will be displaced by 3.52/0.72g= 4.88 g. Therefore displacement value of drug = 4.9 (rounded to one decimal place).

Explanation:

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Answer 2

Answer:

The displacement value of zinc oxide is 5.

Explanation:

• The displacement value refers to the no. of parts by weight of medicament which displaces 1 part by the weight of the base.

• And the volume of suppositories from a particular mould is often constant but the weight varies.
• This is because the densities of medicaments differ from the density of the base which will further affect the amount of the base needed for each suppository.

Given,

→The weight of 8 suppositories is 11.74 g.

To be calculated:

displacement value.

→The weight of 8 suppositories containing Theobroma oil = 1×8 =8g.

→The weight of 8 suppositories containing 40% of zinc oxide ($ZnO$) = 11.74g.

→Now the amount of theobroma oil in 8 suppositories can be calculated as-

$\frac{60}{100}$ × $11.74$g.=$7.044 g.$

→The amount of medicament in 8 suppositories can be calculated as-

$\frac{40}{100}$ × $11.74$ = $4.696g$

→Now the amount of base which is replaced by $4.696g$. of the drug can be calculated as- $8- 7.044g.=0.956g.$

∴ The displacement value can be calculated as-

⇒ $\frac{4.696}{0.956}= 4.912=5 (approx.)$