Question

What is the distance from the Earth's center to a point in space where the gravitational acceleration due to the Earth is 1/24 of its value at the Earth's surface?

Answer 1

g at h is g(r/plus h)^2

1/24 of g equal to g(r/r plus h)^2

g/ 24 equal to g(6400/6400 plus h)^2

1/24 equal to (6400/6400 plus h )^2

root both side

1/root24 equal to 6400/6400 plus h

1/4.90 equal to 6400/ 6400 plus h

(6400 plus h ) equal to 6400 *4.90

6400 plus h equal to 31360

so , h is equal to 31360- 6400 is 24960m