Physics, asked by Shanza21, 1 year ago

What is the distance travelled by a moving car with velocity 15m/s in 2s which decelerates at 2m/s?

Answers

Answered by dhruvsh

a = -2 m/s^2
u = 15 m/s
t = 2 seconds

Therefore,
s = ut +1/2*a*t^2
s = 15*2 - 1/2*2*4
s = 30 - 4 = 26 metres.

dhruvsh: u is the initial velocity of the object

Shanza21: but it is represented by vi

dhruvsh: v is represented for final velocity

divya1261: I think he is saying v1

divya1261: In some question people take inital velocuty v1 and final velocity v2

dhruvsh: yeah so the denotions don't matter

dhruvsh: you can take initial velocity as u or vi or v1 as you wish

dhruvsh: hope now it's clear?

Shanza1062: ok thnx

dhruvsh: no problem

Answered by divya1261

Hope it will help you

divya1261: What

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