what is the equation for finding the answer?
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<AQB = 130°
Here, APBQ is a cyclic Quadrilateral...
So, <AQB + <APB = 180°
130° + < APB = 180°
<APB = 180°- 130°
<APB =50°
.........
now , from the theorem.. the angle subtend by an acr is double at the center from any other point of circle.
So, <AOB = 50°×2 = 100°
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