what is the equation of straight line when passing through the point (3,2) nd perpendicular to the line y=x
Jhalak678:
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x=y
x-y=0
slope of line x-y=0 is 1
therefore the slope of line which is perpendicular to it is -1
the equation of line is (y-2) = -1 (x-3)
y-2 = -x+3
x+y-5=0
x-y=0
slope of line x-y=0 is 1
therefore the slope of line which is perpendicular to it is -1
the equation of line is (y-2) = -1 (x-3)
y-2 = -x+3
x+y-5=0
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