Question

What is the fiftieth term of the arithmetic sequence 3, 7, 11, 15, ... ?

Answer 1

Answer:

3,7,11,15...

see that there is sequence of adding plus4

therfore 3,7,11,15,19,23,27,31,35,39,43,47,51,55, 59 there fore

the fifteenth term is 59

Answer 2

Given,

The arithmetic sequence: 3, 7, 11, 15

To Find,

The fiftieth term =?

Solution,

We can solve the question as follows:

It is given that we have to find the fiftieth term of the arithmetic sequence 3, 7, 11, 15.

The nth term of an A.P. is given as:

$T_{n} = a + (n - 1)d$

Where,

$a = First\: term$

$n = nth\: term$

$d = Common\: difference$

Now, in the given A.P.,

$a = 3$

$n = 50$

The common difference in A.P. is equal to the difference between two consecutive terms which is always a constant. Therefore,

$d = 7 - 3 = 4$

Substituting the given values in the above formula,

$T_{50} = 3 + (50 - 1)4$

      $= 3 + 49*4$

      $= 3 + 196$

      $= 199$

Hence, the fiftieth term of the A.P. is 199.