Question

what is the hcf of 2324 and 8148

Answer 1

to find : HCF of 2324 and 8184

2324 =

first step :  divide 2324 by 2 = 1162

second step :  divide 1162 by 2 = 581

third step :  divide 581 by 7 = 83

and 83 is prime number

So, 2324 = 2*2*7*83

first step :  divide 8184 by 2 = 4092

second step :  divide 4092 by 2 = 2046

third step : divide 2046 by 2 = 1023

fourth step : divide 1023 by 3 = 341

fifth step : divide 341 by 11 = 31

and 31 is a prime number

So, 8184 =  2*2*2*3*11*31

HCF= 2324= 2 * 2 * 7 * 83

      =  8184= 2 * 2 * 2 * 3 * 11 * 31  

HCF = 2*2

HCF = 4

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